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  1. JDK
  2. JDK-4052849

JIT violates expression operands execution order

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      Name: laC46010 Date: 05/18/97



      JIT 210.046 for JDK 1.1.2 doesn't execute some expression operators
      particularly various assignment operators when they are executed before
      other operator completed abruptly.

      In the following example (extracted from JCK's expr17201 test case)
      containing expression

      i = (a = b)[i++];

      it looks like operator [] is executed before ++ operator
      and consecuently "i" variable is not changed accordingly
      before NullPointerException thrown and caught. See log:

      [H:/ld12/java/leo/java/bug/jit/expr] jc -d . expr17201.java
      Symantec Java! JustInTime Compiler Version 210.046 for JDK 1.1.2
      Copyright (C) 1996-97 Symantec Corporation
      [H:/ld12/java/leo/java/bug/jit/expr] ja -verify expr17201
      Symantec Java! JustInTime Compiler Version 210.046 for JDK 1.1.2
      Copyright (C) 1996-97 Symantec Corporation
      Failed.
      i=1
      a=null

      "i" value should be equal to "2" here.

      If we change "i = (a = b)[i++]" to "i = (a = b)[2 + i++]"
      then "i" value is even more strange and equal to "3":

      [H:/ld12/java/leo/java/bug/jit/expr] jc -d . expr17201.java
      Symantec Java! JustInTime Compiler Version 210.046 for JDK 1.1.2
      Copyright (C) 1996-97 Symantec Corporation
      [H:/ld12/java/leo/java/bug/jit/expr] ja -verify expr17201
      Symantec Java! JustInTime Compiler Version 210.046 for JDK 1.1.2
      Copyright (C) 1996-97 Symantec Corporation
      Failed.
      i=3
      a=null

      ---------------------------------------------------------
      // Ident: @(#)expr17201.java 1.1 96/12/10
      // Copyright 12/10/96 Sun Microsystems, Inc. All Rights Reserved


      // package javasoft.sqe.tests.lang.expr172.expr17201;


      import java.io.PrintStream;
      import java.lang.NullPointerException;


      public class expr17201
      {
        public static void main(String args[])
      {
      System.exit(run(args, System.out) + 95/*STATUS_TEMP*/);
      }
       
      public static int run(String args[], PrintStream out)
      {
      int [] a = {0, 11, 22, 33, 44}, b = null;
      int i = 1;

      try {
      i = (a = b)[i++];
      // i = (a = b)[2 + i++];
      } catch (NullPointerException e) {
      if (a == null && i == 2) {
      out.println("Passed.");
      out.println("i=" + i);
      out.println("a=" + a);
      return 0;
      }
      }
      out.println("Failed.");
      out.println("i=" + i);
      out.println("a=" + a);
      return 2;
      }
      }
      ---------------------------------------------------------

      This bug probably causes failures of other JCK111a tests listed below:

      lang/EXPR/expr471/expr47101 res = (a[i] = 1); res assigned before IndexOutOfBoundsException
      lang/EXPR/expr491/expr49101 res = (a[0] += ++i); res assigned before NullPointerException
      lang/EXPR/expr491/expr49102 res = (a[i] += ++j); res assigned before IndexOutOfBoundsException
      lang/STMT/stmt028/stmt02802 wrong a1 value after a1=3; a1 = 10/(a2-5); a1==0 after exception thrown
      lang/EXPR/expr031/expr03101 i = (i / zero) * (j = square(i - 2) + --i); j assigned before ArithmeticException
      lang/EXPR/expr040/expr04001 x = new Triple(i++ / zero, j += i, k *= i + j); x is assigned before exception thrown
      lang/EXPR/expr027/expr02701 y = (i *= power(i, 2)) + (j -= (int) (x-- / power(j, j))) + x--; x has not been decreased before exception thrown from power()
      lang/EXPR/expr062/expr06201 x = new Triple [i++ / zero][j += i][k *= i + j]; i is not increased x = new Triple [i--][j += maxRmd(i, j, k - 3)][k *= j];
      lang/EXPR/expr115/expr11501 x = new expr11501(0)).setVal(++val)
      lang/EXPR/expr115/expr11502 (x = new expr11502(0)).modVal(++x.val)
      lang/EXPR/expr164/expr16401 j = a[a.length / i][++i]; ++ is executed before /
      lang/STMT/stmt072/stmt07201 for ( i1 = 1, i2 = 1, i3 = 1; i1 < 5; i1++, i2+=(10/(2-a1)), i3++ )
      lang/STMT/stmt072/stmt07202 for ( i1 = 1, i2 = 1, i3 = 1; ; i1++, i2+=(10/(2-a1)), i3++ )

      ======================================================================

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            dviswanasunw Deepa Viswanathan (Inactive)
            leosunw Leo Leo (Inactive)
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