>From: Ott Robert <###@###.###>
This does not look like form output to me.


Hi,
I experienced a illegal exception fault under Windows 95 that can be
reproduced by running the code below.

BUG - REPORT
============

1. Seems to be a bug, there is even no Java error handler called when this
   error occurs.

2. Java Development Kit

3. JDK-V1.0 (with java interpreter)

4. When I try to enable/disable all Items of a Menu and there is a separator
   in it, the system crashes without any java exception handler.

5. Hardware : IBM compatible PC 486-DX2/66, 8MB Ram
   Operating System: Windows 95
   
6. Just running with Java interpreter

7. Run the program below with $ java MenuBug
   and then press the 'bug' button.

8. No error message, just directly a Win95 exception

9. No trace information, just directly a Win95 exception


//---------------------------------------------------------------------------
// Sample program that causes an illegal exception on Windows 95
//
// Robert Ott => ###@###.###
//---------------------------------------------------------------------------
import java.lang.*;
import java.awt.*;
 
public class MenuBug extends Frame {
  Button bugMenuButton = new Button("Create the BUG");
  Menu bugMenu = new Menu("BUG-Menu");
 
  MenuBug() {
    super("Demonstration of 'Menu-disable' bug");
    MenuBar b = new MenuBar();
    bugMenu.add("Item 1");
    bugMenu.add("Item 2");
    bugMenu.addSeparator();
    bugMenu.add("Item 3");
    bugMenu.add("Item 4");
    b.add(bugMenu);
    setMenuBar(b);
    bugMenuButton.reshape(80, 100, 140, 23);
    add(bugMenuButton);
    resize(300, 140);
  }
 
  public void disableAll() {
    for(int i = 0; i < bugMenu.countItems(); i++) {
      bugMenu.getItem(i).disable();
    }
  }
 
  public boolean action(Event evt, Object what) {
    if (evt.target.equals(bugMenuButton)) {
      disableAll();
      return true;
    }
    return super.action(evt, what);
  }
 
  static public void main(String args[]) {
    new MenuBug().show();
  }
}