Win32 only: double >= NaN returns true. It should not.
NaN should not be ordered, so any comparison except != should return false. Same
problem with Float.NaN.

Steps to reproduce
Compile and run the attached code
Note: you should not see the Warning message.

public class FloatTest2
{
   public static void main(String argv[])
   {
      double x = 3.1415926;
      double y = Double.NaN;

      System.out.println( "x == " + x );
      System.out.println( "y == " + y );
      System.out.println( ! ( x < y ) );
      System.out.println( x >= y );

      if ( (!( x < y ) ) == ( x >= y ) )
         System.out.println( "Warning! !(x<y) should not equal (x>=y)");

   }
}