Name: mc57594 Date: 02/12/97


The following program produces different results depending
on what exit code is passed in:

public
class tt {
  static foo Foo = null;

  static public void main(String argv[]) {
    System.runFinalizersOnExit(true);
    new foo(1);
    Foo = new foo(2);
    System.exit(Integer.parseInt(argv[0]));
  }

}

class foo {
  int ii;
  foo(int i) {
    ii = i;
    System.out.println("foo(" + i + ") called");
  }
  protected void finalize() {
    System.out.println("finalize called on " + ii);
  }
}

D:\temp>java tt 0
foo(1) called
foo(2) called
finalize called on 1
finalize called on 2

D:\temp>java tt 1
foo(1) called
foo(2) called

If this is intentional, then it should be documented. It would
be nice if the finalization code was run, no matter what the
exit value is.

company - Object Design, Inc. , email - ###@###.###
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