| Issue | Fix Version | Assignee | Priority | Status | Resolution | Resolved In Build |
|---|---|---|---|---|---|---|
| JDK-2016654 | 1.2.0 | Deepa Viswanathan | P4 | Resolved | Fixed | 1.2beta3 |
RandomAccessFile.writeBytes(String) takes a string out writes it out in
bytes. What it neglects to say is it will write each byte out one-by-one.
This caused a performance problem on our machine. Its better to generate
your own byte array from string and then use RandomAccessFile.write(bytebuffer)
Some example truss output
23173: read(8, "CAFEBABE\003\0 -\094\b\0".., 3203) = 3203
23173: brk(0x001749E8) = 0
23173: brk(0x001769E8) = 0
23173: write(17, " R", 1) = 1
23173: write(17, " e", 1) = 1
23173: write(17, " p", 1) = 1
23173: write(17, " l", 1) = 1
23173: write(17, " i", 1) = 1
23173: write(17, " e", 1) = 1
23173: write(17, " d", 1) = 1
23173: write(17, " :", 1) = 1
23173: write(17, " ", 1) = 1
bytes. What it neglects to say is it will write each byte out one-by-one.
This caused a performance problem on our machine. Its better to generate
your own byte array from string and then use RandomAccessFile.write(bytebuffer)
Some example truss output
23173: read(8, "CAFEBABE\003\0 -\094\b\0".., 3203) = 3203
23173: brk(0x001749E8) = 0
23173: brk(0x001769E8) = 0
23173: write(17, " R", 1) = 1
23173: write(17, " e", 1) = 1
23173: write(17, " p", 1) = 1
23173: write(17, " l", 1) = 1
23173: write(17, " i", 1) = 1
23173: write(17, " e", 1) = 1
23173: write(17, " d", 1) = 1
23173: write(17, " :", 1) = 1
23173: write(17, " ", 1) = 1
- backported by
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JDK-2016654 RandomAccessFile.writeBytes(String) is woefully ineffecient
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- Resolved
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- relates to
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JDK-4137835 java.io.RandomAccessFile.writeInt(),readInt() methods results in four kernel cal
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- Closed
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