Name: paC48320 Date: 10/14/97


The Unicode character \u00a0 is supposed to
represent a non-breaking space. Thus I would
expect that a BreakIterator.getLineInstance()
iterator would not use that character as a valid
break position. However, it seems to treat it
the same as a regular space.

Here's a test program:


import java.text.*;

class breaktest
{

public static void main(String args[])
{
String s;

s = "foo\u00a0bar";

BreakIterator boundary = BreakIterator.getLineInstance();
boundary.setText(s);

int start = boundary.first();
int end;

while (true)
{
end = boundary.next();
if (end == BreakIterator.DONE)
break;
System.out.println("start = " + start + " end = " + end);
System.out.println(s.substring(start, end));
start = end;
}
}

}





I would expect that this would print only one run
of text. However, I get two runs: "foo\u00a0"
and "bar".
company - Lotus Development Corp. , email - ###@###.###
======================================================================