Name: joT67522 Date: 01/08/98


compile (w/o warnings ?!?) and run:
class tempSuper{
 String s = "in super";
 String S() { return s;}
}

public class temp extends tempSuper{
 String s = "in sub"; // double def of superclass var
 String A() { return s;}
 String SA() { return super.s;}

// run it

 public static void main( String a[]){
  temp t = new temp();
  tempSuper tSuper = t, tSS;
  System.out.println(
    "\n" + t.S() + // prints "in super"
    "\n" + t.A() + // prints "in sub"
    "\n" + t.SA() + // prints "in super"
    "\n" + tSuper.S() + // prints "in super"
    "\n" + ((temp) tSuper).A()); // prints "in sub"
  System.out.println(
    "\n" + t.s + // prints "in sub"
    "\n" + tSuper.s + // prints "in super"
    "\n" + ((temp) tSuper).s); // prints "in sub"
  }
}
---------------
It is confusing for beginners in Java.
We are reengenering 12,000,000 lines code
into Java with special translators writen by me
and there are "classes" by 20-30,000 lines.

In future development we need about 200 programmers
to be trained to work with this code. They will
create new functions and can easely define some
new dynamic variables which has a same name as
one in superclass used by some method in
a 25,000,000-lines big subclass.

There will not be even a warning by javac about
possible missuse of redefinition of supers vars.
Old methods will stop to work. Some new methods
in superclass will not be able to see
changes because var was also defined in subclass.

Do You can put some -v flag to get more
error/warnings message out from compiler?

I tryed to use private, protected, final etc
to protect code, but without any succes. There
are no mechanism in Java syntax to do it.
(Review ID: 22384)
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