Name: diC59631 Date: 06/11/98


1. Open a server socket on a port
2. Open another one on the same port
   -- Correct behaviour. Does not work.
3. Connect to the server socket
4. Close the server socket
5. Open another one on the same port
   -- Fails with address in use exception
   -- Wrong behaviour
6. Close the socket opened at step 3
7. Repease step 5
   -- Succeeds.

Step 5 succeeds under Solaris. JDK1.02 under
windows NT exhibits the correct behaviour.

Source to test the above case:
import java.net.ServerSocket;
import java.net.Socket;

public class t {
   public static void main(String args[]) throws Exception {
      ServerSocket s1, s2;
      Socket s, ss;
      
      s1 = new ServerSocket(1099);

      try {
s2 = new ServerSocket(1099);
System.out.println("SUCCESS");
System.in.read();
return;
      } catch (Exception e) {
System.out.println("Could not open two listeners at the same port");
e.printStackTrace();
      }
      
      // Connect to host 1099
      s = new Socket("localhost", 1099);
      ss = s1.accept();
      s1.close();
      System.in.read();
      
      try {
s2 = new ServerSocket(1099);
return;
      } catch (Exception e) {
System.out.println("Could not open two listeners at the same port");
System.out.println(" even after closing the first listener");
e.printStackTrace();
      }

      // Nothing at the port
      s.close();
      ss.close();
      
      try {
s2 = new ServerSocket(1099);
return;
      } catch (Exception e) {
System.out.println("This is a serious problem with the OS");
e.printStackTrace();
      }
   }
}
(Review ID: 24672)
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