Name: diC59631 Date: 01/07/99


The default value for the getPatternSeparator() is ',' for the Locale JAPAN and JAPANESE.
But, I think this is not correct. It should be ';' like as the Locale other than JAPAN and JAPANESE.
Because, ',' is the character that used as the grouping character in the integet part in the pattern.
I mean, the same character ',' can not be the grouping charanter and pattern separator.

 Why the default value of the pattern separator for the JAPAN and JAPANESE locale?
 (In the JDK114 return value of the getPatternSeparator() was hard coded as ';'.
  In the JDK116 it return the value in the LocaleElement_ja.java. So is the problem.)

 Please let me know this is a bug?
 Or, there is a significant meaning in that the value should be ',' in JAPAN?
 
 By the way, I am a japanese.

 Regards,


2. Java SOURCE CODE that demonstrates the problem

 The pattern which has the gruoping character in the integer part could not be interpretted correctly.

import java.text.*;
import java.util.*;

class test{
public static void main(String args[]){
DecimalFormat df = (DecimalFormat)NumberFormat.getInstance(Locale.JAPAN);
DecimalFormatSymbols dfs = df.getDecimalFormatSymbols();

df.applyPattern("POSI###,##0;NEGA###,##0");

System.out.println();
System.out.println("set pattern(POSI###,##0;NEGA###,##0)");
System.out.println("pattern separator: " + dfs.getPatternSeparator());
System.out.println("pattern : " + df.toPattern());
System.out.println("localize pattern : " + df.toLocalizedPattern());
System.out.println();
System.out.println(" 10000 value : " + df.format(10000));
System.out.println("-10000 value : " + df.format(-10000));
System.out.println();
}
}
(Review ID: 48545)
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