Trailing space in input stream of Runtime.exec() in Java 2

Name: dbT83986 Date: 04/20/99


Compile and run the following program on Windows NT 4.0 using
Java full version "JDK-1.2-V"
Classic VM (build JDK-1.2-V, native threads)

import java.io.*;

class Test
{
public static void main( String[] args )
{
try
{
Process p = Runtime.getRuntime().exec( "cmd /c echo hello" );
BufferedReader reader = new BufferedReader(
new InputStreamReader( p.getInputStream() ) );
p.waitFor();
String echo = reader.readLine();
System.out.println( "\"" + echo + "\"" );
}
catch ( Exception e )
{
e.printStackTrace();
}
}
}

The output is "hello ". The expected output, which I get in
JDK 1.1.x (inc. 1.1.8) is "hello". Where is the extra space from?
(Review ID: 57217)
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Name: skT88420 Date: 07/22/99

=20
Java Version 1.2.2-W running on Windows NT 4.0

When the Win32Process class constructs a single command string
from the argv String array, an extra blank is appended after
the last arg. This extra blank can be important e.g. with
the cmd.exe builting command "echo".

TEST CASE:
The original test case from bug 4231349:

import java.io.*;

class Test {
    public static void main( String[] args ) {
=09try {
=09=09Process p =3D Runtime.getRuntime().exec( "cmd /c echo hello" );
=09=09BufferedReader reader =3D new BufferedReader(
=09=09=09new InputStreamReader( p.getInputStream() ) );
=09=09p.waitFor();
=09=09String echo =3D reader.readLine();
=09=09System.out.println( "\"" + echo + "\"" );
=09} catch ( Exception e ) {
=09=09e.printStackTrace();
=09}
    }
}


With jdk1.2.2, the test case prints "hello ", while jdk1.1.8
prints "hello" (without the trailing blank).
RELATED BUGS:
4231349
(Review ID: 88255)
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