Name: boT120536 Date: 12/27/2000


Origonal Synopsis
Not properly converting from int to binary/hexadecimal format

?java version "1.3.0"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.3.0-C)
Java HotSpot(TM) Client VM (build 1.3.0-C, mixed mode)

Here is the source Code , for the Data Type Conversion Problem.

package mpt.GeneralFunctions;
import java.io.*;

public class ConvertingTypes {
    private final String cdVERSION = "01.00.000";
                
    public ConvertingTypes() {
    }
    
    public String getVersion() {
        return cdVERSION;
    }
    
    public String int2hexa(int intVAL , int lenVAL) throws
IllegalArgumentException , IOException {
        int workV = intVAL;
        int restoV = 0;
        final int bufLEN = lenVAL;
        StringWriter strBUFF = new StringWriter();
                                  
        if ( lenVAL > 8 ) {
            throw new IllegalArgumentException ("Tamanho maximo deve ser de
oito (8) Bytes.");
        }
        // Verifica se o valor eh menor que 256. Se for faz a conversao
imediatamente e deixa a rotina
        // Apesar de nao ser elegante , eh uma solucao mais eficiente e
simples , evitando
        // controles adicionais no Loop de Conversao
                
        boolean doIT = true;
        boolean doShift = false;
        
        while (doIT) {
            restoV = workV % 16;
            workV = workV / 16;
            if ( doShift ) {
                restoV = restoV * 16;
            }
            doShift = !doShift;
            strBUFF.write(restoV);
            if ( workV == 0 ) {
                doIT = false;
            }
            System.out.println("R=" + restoV + " W="+ workV);
        }
    return strBUFF.toString();
    }
}

Lets suppose that intVal = 144 // 144 = 0x90
or intVal = 141 // 141 = 0x8D.
If I run the class and uses the standard output direct to a file the output is
OK. Expept for the string returned in return Statement , wich returns 63 , wich
is 0x3F.
(Review ID: 113884)
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