Name: ssR10000 Date: 01/25/2001



The Pattern.compile() method incorrectly parses octal sequences.
The root of problem in "private int o()" method.
It parses correctly only two digit octal sequences, but JavaDoc says:
\0n The character with octal value 0n (0 <= n <= 7)
\0nn The character with octal value 0nn (0 <= n <= 7)
\0mnn The character with octal value 0mnn (0 <= m <= 3, 0 <= n <= 7)

See example for more info.

---------------------- example ---------------------
import java.util.regex.*;

public class Test {

    public static void main(String argv[]) {
        System.out.println("Test \\07 pattern...");
        String pattern = "\\o7";
        try {
            Pattern res = Pattern.compile(pattern);
        } catch(PatternSyntaxException e) {
            System.out.println("Pattern : " + pattern);
            System.out.println("Unexpected exception : " + e);
        }

        System.out.println("Test \\0007 pattern...");
        pattern = "\\o007";
        try {
            Pattern res = Pattern.compile(pattern);
            boolean match = Pattern.matches(pattern, "\\u0007");
            if (match) {
                System.out.println("OK. Pattern : " + pattern);
            } else {System.out.println("Not OK.");}
        } catch(PatternSyntaxException e) {
            System.out.println("Pattern : " + pattern);
            System.out.println("Unexpected exception : " + e);
        }

        System.exit(0);
    }
}
---------------------- output ----------------------
Test \07 pattern...
Pattern : \07
Unexpected exception : java.util.regex.PatternSyntaxException: illegal octal escape sequence around index 4
        \07
           ^
Test \0007 pattern...
Not OK.
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