Name: nt126004 Date: 08/29/2001


java version "1.4.0-beta2"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.4.0-beta2-b77)
Java HotSpot(TM) Client VM (build 1.4.0-beta2-b77, mixed mode)


The sample code below should print "b@&@&@". Instead, it errors
out, as shown in the output. Here is the Matcher.find(int)
method, with the problem area highlighted:

public boolean find(int start) {
    if ((start < 0) || (start > to))
                        ^^^^^^^^^^
        throw new IndexOutOfBoundsException("Illegal start index");
    reset();
    return find(start, getTextLength());
}

The problem is that, because this method was the first one called
after the matcher was created, the "to" field is still set to zero.
Either the comparison should be to getTextLength(), or (possibly)
the "to" value could be set in the reset() method.

//====================== sample code ===========================

import java.util.regex.*;

public class PatternTest
{
  public static void main(String[] argv)
  {
    Pattern p = Pattern.compile("\\w{punct}+");
    Matcher m = p.matcher("a@&@&@b@&@&@");
    System.out.println(m.find(1) ? m.group() : "not found");
  }
}

//======================== output =============================

$ java PatternTest
Exception in thread "main" java.lang.IndexOutOfBoundsException:
 Illegal start index
        at java.util.regex.Matcher.find(Matcher.java:425)
        at PatternTest.main(PatternTest.java:9)
(Review ID: 130863)
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