Name: nt126004 Date: 02/07/2002


FULL PRODUCT VERSION :
java version "1.4.0-rc"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.4.0-rc-b91)
Java HotSpot(TM) Client VM (build 1.4.0-rc-b91, mixed mode)

FULL OPERATING SYSTEM VERSION : Linux gescher 2.4.17-PMC-SMP
#4 SMP Thu Jan 31 14:23:30 CET 2002 i686 unknown


A DESCRIPTION OF THE PROBLEM :
When Runtime.exec(cmd, env, execdir) finds cmd in any
directory listed in $PATH, it prepends the directory to the
command name. Then, if I have "." in my $PATH and the
current directory contains an executable called cmd, then
cmd becomes ./cmd.

As Runtime.exec changes to execdir (before executing ./cmd),
if there is also a file called cmd in execdir, this file
will be executed -- and not the one previously found in my
$PATH.

STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
1.Be sure that . is the first directory in your PATH

2.In the current directory do:
   mkdir foo; echo #\!/bin/sh > scr; echo echo hi >> scr;
echo #\!/bin/sh > foo/scr; echo echo ciao >> foo/scr; chmod
u+x scr; chmod u+x foo/scr

3.Run in the current directory the program given below

EXPECTED VERSUS ACTUAL BEHAVIOR :
expected: hi should be printed
actual result: ciao is printed

This bug can be reproduced always.

---------- BEGIN SOURCE ----------
import java.io.*;
public class T {
  public static void main(String[] args) throws Exception {
      String s;
      Process p = Runtime.getRuntime().exec("scr", null, new File("foo"));
      p.waitFor();
      BufferedReader r = new BufferedReader(new
InputStreamReader(p.getInputStream()));
      while ((s=r.readLine()) != null) System.out.println(s);
      System.out.println(p.exitValue());
  }
}

---------- END SOURCE ----------
(Review ID: 139304)
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