Name: gm110360 Date: 02/09/2004


FULL PRODUCT VERSION :
java version "1.5.0-beta"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.5.0-beta-b31)
Java HotSpot(TM) Client VM (build 1.5.0-beta-b31, mixed mode)

ADDITIONAL OS VERSION INFORMATION :
Microsoft Windows XP [Version 5.1.2600]

A DESCRIPTION OF THE PROBLEM :
Situation:
Have a file name with spaces as a URI. created with URI.create(string)
file:/C:/Documents%20and%20Settings/MLambert.NT/.jpluck2/default.jxl
Using URI.resolve(string) to make a new URI. In this case it is an empty string.
Under 1.4, URI.resolve("").toString() returned
file:/C:/Documents%20and%20Settings/MLambert.NT/.jpluck2/
under 1.5 it returns
file:/C:/Documents and Settings/MLambert.NT/.jpluck2/


STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
See example

EXPECTED VERSUS ACTUAL BEHAVIOR :
EXPECTED -
See description
ACTUAL -
See description

ERROR MESSAGES/STACK TRACES THAT OCCUR :
Caused by: java.net.URISyntaxException: Illegal character in path at index 18: file:/C:/Documents and Settings/MLambert.NT/.jpluck2/
        at java.net.URI$Parser.fail(URI.java:2810)
        at java.net.URI$Parser.checkChars(URI.java:2983)
        at java.net.URI$Parser.parseHierarchical(URI.java:3067)
        at java.net.URI$Parser.parse(URI.java:3015)
        at java.net.URI.<init>(URI.java:577)
        at java.net.URI.create(URI.java:839)


REPRODUCIBILITY :
This bug can be reproduced always.

---------- BEGIN SOURCE ----------
import java.net.URI;

/*
 * URITest.java
 *
 * Created on February 4, 2004, 3:46 PM
 */

/**
 *
 * @author MLambert
 */
public class URITest
{
    
    /** Creates a new instance of URITest */
    public URITest()
    {
    }
    
    /**
     * @param args the command line arguments
     */
    public static void main(String[] args)
    {
        String uri = "";
        URI tempU;
        String systemId = "file:/C:/Documents%20and%20Settings/MLambert.NT/.jpluck2/default.jxl";
            tempU = URI.create(systemId);
            System.out.println(tempU.toString());
            tempU = tempU.resolve(uri);
            System.out.println(tempU.toString());
        
        int i = 0;
    }
    
}

---------- END SOURCE ----------

Release Regression From : 1.4.2_03
The above release value was the last known release where this
bug was known to work. Since then there has been a regression.

(Incident Review ID: 237262)
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