FULL PRODUCT VERSION :


A DESCRIPTION OF THE PROBLEM :
Suppose l is a List known to contain only strings. The following code can be used to dump the list into a newly allocated array of String:

     String[] x = (String[]) v.toArray(new String[0]);
 
-> should be

     String[] x = (String[]) l.toArray(new String[0]);



REPRODUCIBILITY :
This bug can be reproduced always.
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