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  1. JDK
  2. JDK-6365133

null is not a constant expression

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    • Icon: Bug Bug
    • Resolution: Duplicate
    • Icon: P4 P4
    • None
    • 5.0
    • specification
    • sparc
    • solaris_10

      FULL PRODUCT VERSION :
      n/a

      A DESCRIPTION OF THE PROBLEM :
      null is a reference literal, but not a literal of String type. In the
      JLS 15.28, constant expression is defined as for literals:

          Literals of primitive type and literals of type String

      Therefore, null is not considered as constant expression. This means that it cannot be a component in a constant expression, even though there is no reason why it cannot be. Consider the following code:

      public class t {
          private static final String FOO = "bar";

          public static void main(String[] args) {
      System.out.println(FOO == null ? 1 : -1);
      System.out.println(FOO == "bar" ? 2 : -2);
      System.out.println(FOO == "xyz" ? 3 : -3);
      switch (args.length) {
      /* 1 */ case (FOO == null ? 1 : -1): System.out.println("null"); break;
      /* 2 */ case (FOO == "bar" ? 2 : -2): System.out.println("bar"); break;
      /* 3 */ case (FOO == "xyz" ? 3 : -3): System.out.println("xyz"); break;
      }
          }
      }

      The compiler complains at 1, presumably because null cannot be part of a constant expression. But the complaint about 1 is not reasonable, especially if 2 and 3 are proper. The value of '((String) "bar") == null)' is clearly known at compile time, as clearly as '((String) "bar") == "bar")'. And if you change the value of FOO to be null, you get a different set of compiler errors: All of 1, 2, and 3 are now flagged as non-constant expressions for this reason.

      I believe that 15.28 should read:

          Literals of primitive type, the null literal, and literals of type String




      REPRODUCIBILITY :
      This bug can be reproduced always.

            abuckley Alex Buckley
            rmandalasunw Ranjith Mandala (Inactive)
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