FULL PRODUCT VERSION :
1.5.0_07
1.6.0-beta2-b85

A DESCRIPTION OF THE PROBLEM :
Using a ZipOutputStream, I cannot create a ZIP file which contains no entries. This should be allowed (see bug 6334003).

ERROR MESSAGES/STACK TRACES THAT OCCUR :
java.util.zip.ZipException: ZIP file must have at least one entry
at java.util.zip.ZipOutputStream.finish(ZipOutputStream.java:304)
at java.util.zip.DeflaterOutputStream.close(DeflaterOutputStream.java:146)
at java.util.zip.ZipOutputStream.close(ZipOutputStream.java:321)
at Test.main(Test.java:9)


REPRODUCIBILITY :
This bug can be reproduced always.

---------- BEGIN SOURCE ----------
// Try to create a ZIP file with no entries. This will fail with
// the following exception: "ZIP file must have at least one entry".
// See also bug 6334003.

import java.io.FileOutputStream;
import java.util.zip.ZipOutputStream;

public class Test {

    public static void main(String[] args) {
        try {
            ZipOutputStream zip = new ZipOutputStream(new FileOutputStream("test.zip"));
            zip.close();
        }
        catch(Exception ex) {
            ex.printStackTrace();
        }
    }

}

---------- END SOURCE ----------