FULL PRODUCT VERSION :
java version 1.5.0_12

ADDITIONAL OS VERSION INFORMATION :
Microsoft Windows XP [Version 5.1.2600]

A DESCRIPTION OF THE PROBLEM :
Java.math.BigDecimal reading 5.675 as 5.67499999999.

I have tried the following code snippet -


public static void main(String[] args) {
double number = 5.675;
Double d = new Double(number);
BigDecimal bd = new BigDecimal(number);
bd = bd.setScale(2, BigDecimal.ROUND_HALF_UP);
System.out.println(bd.toString());
}


I am getting the response as 5.67, whereas it should be 5.68.

STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
Please run the code snippet in Description section to reproduce the scenario.

EXPECTED VERSUS ACTUAL BEHAVIOR :
EXPECTED -
Should get the result as 5.68
ACTUAL -
5.67 is coming instead.

REPRODUCIBILITY :
This bug can be reproduced always.

---------- BEGIN SOURCE ----------
public static void main(String[] args) {
double number = 5.675;
Double d = new Double(number);
BigDecimal bd = new BigDecimal(number);
bd = bd.setScale(2, BigDecimal.ROUND_HALF_UP);
System.out.println(bd.toString());
}

---------- END SOURCE ----------

CUSTOMER SUBMITTED WORKAROUND :
We can do the rounding manually -

public class DoubleOperation {

private static int ROUND_HALF_UP = 4;

public static BigDecimal setScale(Double number, int precision, int mode){
String numberString = number.toString();
int decimalIndex = numberString.indexOf('.');
numberString = numberString.substring(0, decimalIndex + precision + 2);
BigDecimal num = new BigDecimal(numberString);
System.out.println(Integer.parseInt(numberString.substring(numberString.length() - 1)));

if(mode == ROUND_HALF_UP){
if(Integer.parseInt(numberString.substring(numberString.length() - 1)) >= 5){
num = num.setScale(precision, BigDecimal.ROUND_CEILING);
}else{
num = num.setScale(precision, BigDecimal.ROUND_FLOOR);
}
}

return num;
}

}