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  1. JDK
  2. JDK-6975010

Incorrect Handling of Empty Source Files and Imports

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    • x86
    • linux

      FULL PRODUCT VERSION :
      java version "1.6.0_20"
      Java(TM) SE Runtime Environment (build 1.6.0_20-b02)
      Java HotSpot(TM) Server VM (build 16.3-b01, mixed mode)

      ADDITIONAL OS VERSION INFORMATION :
      Linux thirtyseven 2.6.32-5-686-bigmem #1 SMP Tue Jun 1 05:38:08 UTC 2010 i686 GNU/Linux

      A DESCRIPTION OF THE PROBLEM :
      Consider a case in which three files exist in the source tree: foo/Main.java, foo/Test.java, and bar/Test.java . Suppose foo/Main.java contains an import statement "import bar.*". Suppose also that foo/Main.java contains a reference to a type named "Test".

      If foo/Test.java contains a top-level class declaration named "Test", the reference in Main means the type contained in foo/Test.java (JLS v3 S6.5.5, S7.5.2). Specifically, the import statement, because it is on-demand, has no impact on that reference. This is correct behavior.

      However, it is possible for Test.java to contain no top-level type declarations (S7.3). If no such top-level type declaration appears and bar/Test.java contains a top-level type named "Test", the name "Test" refers to the type declared in bar/Test.java . In practice, however, compilation fails because the compiler expects to find a class foo.Test.

      This bug was discovered while I was confirming my understanding of how the type namespace works in Java.

      STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
      Create a new source directory (termed $src henceforth) and create subdirectories $src/example and $src/example2. Create a file $src/example/Main.java containing the following code:

          package example;

          import example2.*;

          public class Main
          {
              public static void main(String[] arg)
              {
                  Test t = new Test();
                  System.out.println(t.getClass());
              }
          }

      Create a file $src/example/Test.java containing the following code:

          package example;
          //public class Test {}

      Create a file $src/example2/Test.java containing the following code:

          package example2;

          public class Test {}

      Attempt to compile all three source files.

      EXPECTED VERSUS ACTUAL BEHAVIOR :
      EXPECTED -
      The three source files should compile successfully. The output file example/Main.class should refer to the class contained in example2/Test.class.
      ACTUAL -
      Compilation fails; no binary output is produced.

      ERROR MESSAGES/STACK TRACES THAT OCCUR :
      ./example/Main.java:9: cannot access example.Test
      bad class file: ./example/Test.java
      file does not contain class example.Test
      Please remove or make sure it appears in the correct subdirectory of the classpath.
              Test t = new Test();
              ^
      1 error


      REPRODUCIBILITY :
      This bug can be reproduced always.

      ---------- BEGIN SOURCE ----------
      Contents of example/Main.java:

          package example;

          import example2.*;

          public class Main
          {
              public static void main(String[] arg)
              {
                  Test t = new Test();
                  System.out.println(t.getClass());
              }
          }

      Contents of example/Test.java:

          package example;
          //public class Test {}

      Contents of example2/Test.java:

          package example2;

          public class Test {}
      ---------- END SOURCE ----------

      CUSTOMER SUBMITTED WORKAROUND :
      No workaround is currently available short of deleting or moving the offending source file (example/Test.java). This is a bug because the source file meets the requirements, both syntactic and semantic, of the Java Language Specification.

            Unassigned Unassigned
            webbuggrp Webbug Group
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