If I try to call method handle for a virtual method without binding it to an object, the exception message says the following:

java.dyn.WrongMethodTypeException: (Ljava/lang/String;Ljava/lang/Integer;F)J cannot be called as (Ljava/lang/String;Ljava/lang/Integer;F)J
        at jsr292test01.main(jsr292test01.java:24)

This is confusing for a user: signatures do match, why wrong type?

Test program:

$ cat jsr292test01.java
import java.dyn.MethodHandle;
import java.dyn.MethodHandles;
import java.dyn.MethodType;

public class jsr292test01 {

public long method(String a, Integer b, float c) {
return 0;
}

public static void main(String[] args) {
try {
MethodHandle mh = MethodHandles.lookup().findVirtual(jsr292test01.class, "method",
MethodType.methodType(long.class, String.class, Integer.class, float.class));

jsr292test01 me = new jsr292test01();
long l;

System.err.println("1");
l = (long) mh.bindTo(me).invokeExact("a", new Integer(1), 3F); // OK

System.err.println("2");
l = (long) mh.invokeExact("a", new Integer(1), 3F); // Exception

} catch ( Throwable t ) {
t.printStackTrace();
}
}

}
$