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Bug
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Resolution: Fixed
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P2
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None
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Verified
Because a lambda expressions is treated as a Primary, it can (grammatically) appear as the left operand to some binary expression; or (as intended) the operator and the right operand could be considered part of the lambda body.
() -> x + 1
(() -> x) + 1
vs.
() -> (x + 1)
() -> x + 1
(() -> x) + 1
vs.
() -> (x + 1)