FULL PRODUCT VERSION :
java version "1.8.0_05"
Java(TM) SE Runtime Environment (build 1.8.0_05-b13)
Java HotSpot(TM) 64-Bit Server VM (build 25.5-b02, mixed mode)

ADDITIONAL OS VERSION INFORMATION :
Mac OS X 10.9.3

A DESCRIPTION OF THE PROBLEM :
Consider this snippet of java 8 code:

public class Generics {
  public static <V, E extends Exception> V f(CheckedCallable1<V, E> callable) throws E {
    return callable.call();
  }
  public static <V, E extends Exception> V g(CheckedCallable2<V, E> callable) throws E {
    return callable.call();
  }
  public static void main(String[] args) throws Exception {
    f(() -> 1);
    g(() -> 1);
  }
}

interface Callable<V> {
  V call() throws Exception;
}

interface CheckedCallable1<V, E extends Exception> {
  V call() throws E;
}

interface CheckedCallable2<V, E extends Exception> extends Callable<V> {
  @Override V call() throws E;
}

The lambda at the call to f compiles fine, whereas the lambda at the call to g does not compile, but rather gives this compile error:

Error:(10, 7) java: call() in <anonymous Generics$> cannot implement call() in CheckedCallable2
  overridden method does not throw java.lang.Exception

I believe this is a compiler bug, in particular since the identical code with Exception replaced with IOException compiles fine.

Additional details are at http://stackoverflow.com/questions/24199148/lambdas-and-functional-interfaces-with-generic-throw-clauses

STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
Compile the following java code:

public class Generics {
  public static <V, E extends Exception> V f(CheckedCallable1<V, E> callable) throws E {
    return callable.call();
  }
  public static <V, E extends Exception> V g(CheckedCallable2<V, E> callable) throws E {
    return callable.call();
  }
  public static void main(String[] args) throws Exception {
    f(() -> 1);
    g(() -> 1);
  }
}

interface Callable<V> {
  V call() throws Exception;
}

interface CheckedCallable1<V, E extends Exception> {
  V call() throws E;
}

interface CheckedCallable2<V, E extends Exception> extends Callable<V> {
  @Override V call() throws E;
}

EXPECTED VERSUS ACTUAL BEHAVIOR :
EXPECTED -
I expect this code to compile.
ACTUAL -
The call to g results in the following compile error:

Error:(10, 7) java: call() in <anonymous Generics$> cannot implement call() in CheckedCallable2
  overridden method does not throw java.lang.Exception

ERROR MESSAGES/STACK TRACES THAT OCCUR :
Error:(10, 7) java: call() in <anonymous Generics$> cannot implement call() in CheckedCallable2
  overridden method does not throw java.lang.Exception

REPRODUCIBILITY :
This bug can be reproduced always.

---------- BEGIN SOURCE ----------
public class Generics {
  public static <V, E extends Exception> V f(CheckedCallable1<V, E> callable) throws E {
    return callable.call();
  }
  public static <V, E extends Exception> V g(CheckedCallable2<V, E> callable) throws E {
    return callable.call();
  }
  public static void main(String[] args) throws Exception {
    f(() -> 1);
    g(() -> 1);
  }
}

interface Callable<V> {
  V call() throws Exception;
}

interface CheckedCallable1<V, E extends Exception> {
  V call() throws E;
}

interface CheckedCallable2<V, E extends Exception> extends Callable<V> {
  @Override V call() throws E;
}
---------- END SOURCE ----------

CUSTOMER SUBMITTED WORKAROUND :
1) Don't extend a functional interface without a generic throws clause in a functional interface with a generic throws clause.

or

2) Use a subclass of Exception on the functional interface without generic throws clause.