FULL PRODUCT VERSION :
Java SE runtime environment (Build 1.8.0_74-b02)
Ava HotSpot 64-bit server VM (Build 25.74-b02, mixed mode)

ADDITIONAL OS VERSION INFORMATION :
Linux version 3.16.7-24-desktop (SUSE Linux, x64)

A DESCRIPTION OF THE PROBLEM :
There is wrong number cast by the ternary operator. It is easier to present the little code part:

double x = 10.5;
Number tmp = (/* true or false */) ? (int)x : (double)x;

As I wrote in other text boxes under this, if it is true branch, tmp will be a double number (with Double class). What is interesting, if I put (int)x : (int)x , ternary operator will cast to the integer class both branches.

STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
1) Create a new project and in main method put next:
2) Create a basic double variable x (as in my example, 10.5)
3) Create a variable tmp with class Number and put in this variable casted value (int)x : (double)x by the ternary operator
4) Switch ternary boolean value and print tmp variable's class. In false case, it will be Double, but in true case it will be Double too, actually

EXPECTED VERSUS ACTUAL BEHAVIOR :
EXPECTED -
Double : 10.5
Integer : 10
Integer : 10
ACTUAL -
Double : 10.5
Double : 10.0
Integer : 10

REPRODUCIBILITY :
This bug can be reproduced always.

---------- BEGIN SOURCE ----------
double x = 10.5;

// correct
Number tmp = (0 == 1) ? (int)x : (double)x;
System.out.println(tmp.getClass().getSimpleName() + " : " + tmp);

// wrong
Number tmp2 = (1 == 1) ? (int)x : (double)x;
System.out.println(tmp2.getClass().getSimpleName() + " : " + tmp2);

// correct
Number tmp3 = (1 == 1) ? (int)x : (int)x;
System.out.println(tmp3.getClass().getSimpleName() + " : " + tmp3);
---------- END SOURCE ----------

CUSTOMER SUBMITTED WORKAROUND :
Just use if (); else (); construction