A DESCRIPTION OF THE REQUEST :
private static int binarySearch0(int[] a, int fromIndex, int toIndex,
int key) {
int low = fromIndex;
int high = toIndex - 1;

while (low <= high) {
int mid = (low + high) >>> 1;
int midVal = a[mid];

if (midVal < key)
low = mid + 1;
else if (midVal > key)
high = mid - 1;
else
return mid; // key found
}
return -(low + 1); // key not found.
}

JUSTIFICATION :
for ex int[] a={1,2...........100};
and I am searching elements that is not in the range of this array. for ex: 199
but it still executes while loop multiple time

EXPECTED VERSUS ACTUAL BEHAVIOR :
EXPECTED -
Actual behavior should be like this without executing while loop

-1
ACTUAL -
elements is out of range of array but still executing while loop

LOW:0>>>>>>>>>HIGH::54
LOW:28>>>>>>>>>HIGH::54
LOW:42>>>>>>>>>HIGH::54
LOW:49>>>>>>>>>HIGH::54
LOW:52>>>>>>>>>HIGH::54
LOW:54>>>>>>>>>HIGH::54
-56

---------- BEGIN SOURCE ----------
private static int binarySearch0(int[] a, int fromIndex, int toIndex,
int key) {
int low = fromIndex;
int high = toIndex - 1;
                
// we can add below if condition
if(key>a[a.length-1])
return -(low+1);
// end

while (low <= high) {
int mid = (low + high) >>> 1;
int midVal = a[mid];

if (midVal < key)
low = mid + 1;
else if (midVal > key)
high = mid - 1;
else
return mid; // key found
}
return -(low + 1); // key not found.
}
---------- END SOURCE ----------

CUSTOMER SUBMITTED WORKAROUND :
Required to add below line ::

// we can add below if condition
if(key>a[a.length-1])
return -(low+1);
// end