FULL PRODUCT VERSION :
java version "1.8.0_161"
Java(TM) SE Runtime Environment (build 1.8.0_161-b12)
Java HotSpot(TM) 64-Bit Server VM (build 25.161-b12, mixed mode)


ADDITIONAL OS VERSION INFORMATION :
Linux nikhil-XPS-15-9560 4.13.0-36-generic #40~16.04.1-Ubuntu SMP Fri Feb 16 23:25:58 UTC 2018 x86_64 x86_64 x86_64 GNU/Linux

A DESCRIPTION OF THE PROBLEM :
SimpleDateFormat, parse method doesn't throw Parse exception in case of wrong format.

STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
Steps
1. Create SimpleDateFormat with pattern "dd/MM/yyyy"
2. setLenient to false
3. call sdf.parse("16/05/1985R")


EXPECTED VERSUS ACTUAL BEHAVIOR :
EXPECTED -
sdf.parse("16/05/1985R") should throw ParseException
ACTUAL -
No Exception thrown

REPRODUCIBILITY :
This bug can be reproduced always.

---------- BEGIN SOURCE ----------
//This test will FAIL
@Test
    public void throwExceptionWhenInvalidDateFormatWithSimpleDateFormat() {
        final SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
        sdf.setLenient(true);
            assertThrows(ParseException.class, () -> sdf.parse("16/05/1985R"));

    }

//This test will PASS
@Test
    public void throwExceptionWhenInvalidDateFormatWithSimpleDateFormat() {
        final SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
        sdf.setLenient(true);
            assertThrows(ParseException.class, () -> sdf.parse("R16/05/1985"));

    }
---------- END SOURCE ----------

CUSTOMER SUBMITTED WORKAROUND :
Use

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd/MM/yyyy");
LocalDate.parse("", formatter);

This will throw DateTimeParseException