ADDITIONAL SYSTEM INFORMATION :
Win10
java version "15.0.1" 2020-10-20
Java(TM) SE Runtime Environment (build 15.0.1+9-18)
Java HotSpot(TM) 64-Bit Server VM (build 15.0.1+9-18, mixed mode, sharing)


A DESCRIPTION OF THE PROBLEM :
See above

STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
Compile and run the code

EXPECTED VERSUS ACTUAL BEHAVIOR :
EXPECTED -
Character comparison should be correctly evaluated also in a ternary operator
ACTUAL -
In the line
obj= (cType=='I') ? Integer.valueOf(s) : Double.valueOf(s);

the character comparison is evaluated as "false", which is not correct.

---------- BEGIN SOURCE ----------
public class Ternary {

  public static void main(String args[]) {
    char cType= 'I';
    String s= "10";
    Object obj= s;
    System.out.println(obj);
    System.out.println(cType=='I'); // Character comparison correctly evaluated.
    obj= (cType=='I') ? Integer.valueOf(s) : Double.valueOf(s); // Incorrectly
    System.out.println(obj+" "+(obj instanceof Double)); // Unexpected

// if-else construction works fine.
    if (cType=='I')
      obj= Integer.valueOf(s);
    else
      obj= Double.valueOf(s);
    System.out.println(obj+" "+(obj instanceof Double));
    System.out.println((cType=='I') ? "cType is I" : "cType is not I");
    System.exit(0);
  }
}

---------- END SOURCE ----------

CUSTOMER SUBMITTED WORKAROUND :
Use if-else construction.

FREQUENCY : always